Postgraduate Mathematics III task 114: Find the distance between (5,2) and (8,6).
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
Practice China questions with answers and explanations.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
Rewrite the value using base 4: 256 = 4^4. Matching exponents gives x = 4.
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Use the circle-area formula A = πr². Substituting r = 8 gives A = π × 8² = 64π.
An antiderivative is 3/2 x²+1x. At x=4, the value is 28.0.
The dot product is 3×3+2×5=19.
Percentage=(14/29)×100=48.28.
Subtract 10 from both sides and divide by 2: x = (20-10)/2 = 5.
By Vieta’s formula, the sum of the roots equals the coefficient 16.
aₙ=a₁+(n−1)d=9+(15−1)×5=79.
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The sum is n(n+1)/2=10, so the mean is 10/4.
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There are 2 favourable outcomes out of 9 equally likely outcomes, so P(red)=2/9.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.