Postgraduate Mathematics III task 17: A bag contains 5 red and 6 blue balls. One ball is drawn at random. What is P(red)?
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There are 5 favourable outcomes out of 11 equally likely outcomes, so P(red)=5/11.
Practice China questions with answers and explanations.
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There are 5 favourable outcomes out of 11 equally likely outcomes, so P(red)=5/11.
Rewrite the value using base 4: 256 = 4^4. Matching exponents gives x = 4.
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Use the circle-area formula A = πr². Substituting r = 8 gives A = π × 8² = 64π.
By Vieta’s formula, the sum of the roots equals the coefficient 18.
aₙ=a₁+(n−1)d=10+(7−1)×3=28.
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The sum is n(n+1)/2=55, so the mean is 55/10.
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There are 4 favourable outcomes out of 9 equally likely outcomes, so P(red)=4/9.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=9x²+16x. Substituting x=3 gives 129.
An antiderivative is 3/2 x²+3x. At x=4, the value is 36.0.
The dot product is 3×4+4×3=24.
Subtract 11 from both sides and divide by 8: x = (75-11)/8 = 8.