Senior-secondary mathematics task 138: Find the distance between (0,3) and (3,7).
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
Practice China questions with answers and explanations.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=9x²+14x. Substituting x=1 gives 23.
An antiderivative is 1/2 x²+3x. At x=2, the value is 8.0.
Percentage=(6/31)×100=19.35.
Subtract 6 from both sides and divide by 7: x = (20-6)/7 = 2.
Choose an option to check your answer.
There are 3 favourable outcomes out of 11 equally likely outcomes, so P(red)=3/11.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=6x²+12x. Substituting x=4 gives 144.
An antiderivative is 4/2 x²+2x. At x=5, the value is 60.0.
The dot product is 4×4+3×6=34.
Rewrite the value using base 5: 3125 = 5^5. Matching exponents gives x = 5.
Choose an option to check your answer.
Use the circle-area formula A = πr². Substituting r = 5 gives A = π × 5² = 25π.