JEE Main Mathematics numerical 192: Enter the positive value of |10²−11|.
Correct Answer: 89
Explanation:
89
Practice India questions with answers and explanations.
89
Area=½×11×16=88.0.
48
517
Area=½×24×17=204.0.
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Four sigma bonds require tetrahedral sp3 hybridisation.
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Charles law states V∝T at constant pressure.
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The common Aufbau order places 4s before 3d.
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Oxidation is electron loss.
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A Lewis base donates an electron pair.
Vieta gives r+s=29.
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Four sigma bonds require tetrahedral sp3 hybridisation.