MHT-CET Mathematics item 13: For vector v=(6,4), find |v|².
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|v|²=6²+4²=52.
Practice India questions with answers and explanations.
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|v|²=6²+4²=52.
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f′(x)=2x, so f′(7)=14.
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By Vieta, α+β=19.
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(7+4)/2=5.5.
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By Vieta, α+β=7.
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Determinant=4×6=24.
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|v|²=5²+8²=89.
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f′(x)=2x, so f′(6)=12.
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4s is filled before 3d in the standard sequence.
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Four sigma bonds give tetrahedral sp³ hybridisation.
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For fixed gas at constant temperature, PV is constant.
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NH₃ can donate a lone pair.