KCET Mathematics item 13: For vector v=(7,5), find |v|².
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|v|²=7²+5²=74.
Practice India questions with answers and explanations.
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|v|²=7²+5²=74.
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f′(x)=2x, so f′(8)=16.
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By Vieta, α+β=13.
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Determinant=2×5=10.
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|v|²=3²+7²=58.
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f′(x)=2x, so f′(4)=8.
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(5+3)/2=4.0.
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By Vieta, α+β=11.
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(8+5)/2=6.5.
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By Vieta, α+β=16.
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Determinant=10×9=90.
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For fixed gas at constant temperature, PV is constant.