Common Test Mathematics II/B/C practice 3: For f(x)=5x²+3x, find f′(7).
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f′(x)=10x+3; substitute x=7.
Practice Japan questions with answers and explanations.
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f′(x)=10x+3; substitute x=7.
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An antiderivative is 6x²+6x, giving 432.
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The conjugate changes the sign of the imaginary part.
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z=(x−mean)/sd=2.
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Repeated multiplication gives 31381059609.
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log x + log y = log(xy).
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The sum is 3(1+…+5)=3×15=45.
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10% of 30 = 3.
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Mean = (15 + 19 + 5 + 34)/4 = 18.25.
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f(7)=2×7+3=17.
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Use combinations: C(11,3) = 165.
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Probability = favourable outcomes ÷ total outcomes.