Practice Pakistan questions with answers and explanations.
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The sequence moves backward by three letters.
Three letters before Q is N.
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The terms follow n(n+1).
The next value is 6 × 7 = 42.
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The forward jumps are 3, 4, 5, and 6.
The next jump is 7, taking T to A after wrapping.
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Every term is multiplied by 2.
Therefore, 48 × 2 = 96.
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The letter positions are 1, 4, 9, and 16.
The next square position is 25, which is Y.
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The increases are 5, 10, 15, and 20.
The next increase is 25, giving 85.
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The jumps are +3, +4, and +5.
The next jump is +6, taking O to U.
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The operations alternate between ×2 and +3.
After 42, add 3 to obtain 45.
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The backward jumps are 2, 3, and 4 letters.
Moving 5 letters back from D gives Y after wrapping.
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The decreases are 5, 10, 15, and 20.
The next decrease is 25, leaving 25.
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The series alternates from the start and end of the alphabet.
After C-X comes D.
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Each term is n² + 1 for n = 1, 2, 3, 4, 5.
The next term is 6² + 1 = 37.
