Practice Pakistan questions with answers and explanations.
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Travel time is 210 ÷ 70 = 3 hours.
Three hours after 8:00 a.m. is 11:00 a.m.
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Their closing speed is 20 + 25 = 45 km/h.
Time = 90 ÷ 45 = 2 hours.
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The path forms a right triangle with legs 5 and 12.
By Pythagoras, distance is √(25 + 144) = 13 km.
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The first part takes 2 hours and the second takes 1 hour.
The total travel time is 3 hours.
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The speed is 90 × 5/18 = 25 m/s, so total distance is 25 × 24 = 600 m.
Subtracting the train length gives a bridge length of 400 m.
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Downwind speed is 300 km/h and upwind speed is 200 km/h.
Wind speed is half their difference: 50 km/h.
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Subtract 7 from both sides of the equation.
This gives x = 19 - 7 = 12.
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Divide both sides by the coefficient 3.
Thus, x = 27 ÷ 3 = 9.
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Subtract 5 to get 2x = 12.
Dividing by 2 gives x = 6.
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Move variable terms to one side and constants to the other.
Then 3x = 15, so x = 5.
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Multiply both sides by 4.
Thus, x = 7 × 4 = 28.
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Adding the equations gives 2x = 14, so x = 7.
Substituting into x + y = 10 gives y = 3.
