Practice Pakistan questions with answers and explanations.
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Each position in the three-letter group advances by one letter.
Thus, CEG becomes DFH.
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The jumps are +2, +3, +4, and +5.
The next jump is +6, taking P to V.
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The backward jumps are 3, 4, and 5 letters.
The next jump is 6, taking M to G.
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The successive increases are 4, 6, 8, and 10.
The next increase is 12, so 41 + 12 = 53.
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The terms follow n(n + 1): 1×2, 2×3, 3×4, and so on.
The next term is 6×7 = 42.
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The operations alternate between multiplying by 3 and dividing by 2.
After 18, multiply by 3 to get 54.
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Each term is the sum of the preceding two terms.
Thus, 5 + 8 = 13.
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The sequence skips one letter each time.
After G, the next alternate letter is I.
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The sequence moves backward by two letters.
Two letters before T is R.
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Each term advances by three alphabet positions.
K plus three letters gives N.
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Each term is multiplied by 2.
Therefore, 96 × 2 = 192.
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The sequence follows repeated multiplication by 2.
Thus, 40 × 2 = 80.
