Practice Pakistan questions with answers and explanations.
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There are 4 aces among 52 cards.
Thus, the probability is 4/52 = 1/13.
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The equally likely outcomes are HH, HT, TH, and TT.
Exactly one head occurs in HT and TH, giving 2/4 = 1/2.
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Average the x-coordinates and the y-coordinates separately.
The midpoint is ((2 + 8)/2, (3 + 7)/2) = (5, 5).
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There are 36 equally likely ordered outcomes.
Six outcomes have sum 7, so the probability is 6/36 = 1/6.
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Slope is change in y divided by change in x.
Thus, (10 - 2)/(5 - 1) = 8/4 = 2.
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An event and its complement have total probability 1.
Thus, P(not A) = 1 - 0.35 = 0.65.
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A horizontal line has a constant y-coordinate.
Therefore, an equation of the form y = constant is horizontal.
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For independent events, multiply their probabilities.
Thus, 1/2 × 1/3 = 1/6.
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A vertical line has a constant x-coordinate.
Therefore, x = -3 represents a vertical line.
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There are 2 favorable blue balls out of 5 total balls.
The probability is therefore 2/5.
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The inner rectangle measures 46 m by 26 m, with area 1,196 m².
The full area is 1,500 m², so the path area is 304 m².
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The intersection contains elements common to both sets.
Only 3 appears in both A and B.
