Practice Pakistan questions with answers and explanations.
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The middle position in a row of seven is position four.
It is fourth from both ends.
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The relation is O > M > N > P.
Therefore, O is definitely more expensive than M.
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P at the far left occupies position 1, so Q must occupy position 2.
R remains in position 3.
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D must be left of A, A left of B, and B left of C.
This gives D-A-B-C.
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Moving three places right from position 2 reaches position 5.
Thus, F is fifth from the left.
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The consecutive order is P-Q-R.
If P is second, Q is third and R is fourth.
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The condition explicitly places A immediately beside C.
No other person can occupy that adjacent position.
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H is sixth from the left in a seven-seat row.
Positions 3, 4, and 5 lie between G and H.
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The chain A-B-C-D must remain in that order.
With E at the far left, the chain fills positions 2 to 5, placing D at the far right.
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K is immediately to the left of J.
With J fourth, K is third.
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Total = left rank + right rank - 1.
Thus, 15 + 18 - 1 = 32.
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Removing five candidates ahead moves the candidate up five places.
The new rank is 20 - 5 = 15.
