Practice Pakistan questions with answers and explanations.
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For ax² + bx + c = 0, the product of roots is c/a.
Here, 20/1 = 20.
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The digit sum of 568 is 19, which leaves remainder 1 when divided by 9.
Adding 8 makes the digit sum 27, divisible by 9.
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Substitute x = -4 into the expression.
Then y = 3(-4) - 2 = -14.
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The largest two-digit multiple of 7 is 7 × 14.
This equals 98.
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Slope-intercept form is y = mx + c.
With m = 2 and c = 3, the equation is y = 2x + 3.
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The LCM uses prime powers 2³, 3, and 5.
Their product is 8 × 3 × 5 = 120.
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A point with x = 0 gives the y-intercept 4.
Using y = mx + c with m = -1 gives y = -x + 4.
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The second number is product divided by the first number.
Thus, 216 ÷ 18 = 12.
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The sum of the roots is 6.
Their average is 6/2 = 3.
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For two positive integers a and b, gcd(a,b) × lcm(a,b) = ab.
This identity links common factors and common multiples.
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At 3:00, the minute hand points at 12 and the hour hand at 3.
Three hour intervals correspond to 3 × 30° = 90°.
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If n ≡ 4 mod 7, then 2n ≡ 8 mod 7.
The remainder of 8 divided by 7 is 1.
