A machine depreciates by 10% each year. If its current value is Rs. 50,000, what will it be worth after 2 years?
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Each year, 90% of the previous value remains.
Thus, 50,000 × 0.9² = Rs. 40,500.
Practice Pakistan questions with answers and explanations.
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Each year, 90% of the previous value remains.
Thus, 50,000 × 0.9² = Rs. 40,500.
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Compound growth gives 20,000 × 1.05².
The result is 22,050.
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One-year compound amount is principal plus 12% interest.
Thus, 20,000 × 1.12 = Rs. 22,400.
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Initially, milk is 42 liters and water is 18 liters.
For a 7:5 ratio with 42 liters milk, water must be 30 liters, so add 12.
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Let the numbers be 5k and 8k; then (5k + 9)/(8k + 9) = 2/3.
Solving gives k = 9, so the smaller number is 45.
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Profit equals selling price minus cost price.
Thus, 920 - 800 = Rs. 120.
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The weighted sum is 70 × 2 + 90 × 3 = 410.
Dividing by the total weight 5 gives 82.
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A 10% loss on Rs. 1,200 is Rs. 120.
Subtracting gives a selling price of Rs. 1,080.
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The total score is 20 × 60 + 30 × 70 = 3,300.
Dividing by 50 students gives 66.
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The selling price is 125% of the cost price.
Thus, cost price = 1,500 ÷ 1.25 = Rs. 1,200.
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The total ratio parts are 7, so one part is 35/7 = 5 liters.
Water is two parts, or 10 liters.
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The discount is 15% of Rs. 2,000, which is Rs. 300.
The sale price is Rs. 2,000 - Rs. 300 = Rs. 1,700.