Practice Pakistan questions with answers and explanations.
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Triangle area is one-half × base × height.
Thus, 1/2 × 10 × 6 = 30 cm².
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Average the x-coordinates and the y-coordinates separately.
The midpoint is ((2 + 8)/2, (3 + 7)/2) = (5, 5).
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Parallelogram area is base times perpendicular height.
Thus, 15 × 8 = 120 cm².
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Slope is change in y divided by change in x.
Thus, (10 - 2)/(5 - 1) = 8/4 = 2.
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Area is one-half × sum of parallel sides × height.
Thus, 1/2 × 22 × 5 = 55 cm².
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Circumference is 2πr.
Thus, 2 × 22/7 × 7 = 44 cm.
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Circle area is πr².
Thus, 22/7 × 49 = 154 cm².
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A 90° arc is one quarter of the circumference.
The circumference is 88 cm, so the arc is 22 cm.
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Sector area is angle/360 × πr².
Thus, 60/360 × 36π = 6π cm².
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Cube volume is side cubed.
Thus, 4³ = 64 cm³.
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A cube has six square faces, each of area 25 cm².
Thus, total area is 6 × 25 = 150 cm².
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Cuboid volume is length × width × height.
Thus, 8 × 5 × 3 = 120 cm³.
