Practice Pakistan questions with answers and explanations.
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Travel time is 210 ÷ 70 = 3 hours.
Three hours after 8:00 a.m. is 11:00 a.m.
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The discriminant is b² - 4ac.
Here it is 4² - 4(1)(1) = 16 - 4 = 12.
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Their closing speed is 20 + 25 = 45 km/h.
Time = 90 ÷ 45 = 2 hours.
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A zero discriminant makes the square-root term in the formula zero.
Both solutions therefore coincide.
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The path forms a right triangle with legs 5 and 12.
By Pythagoras, distance is √(25 + 144) = 13 km.
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When multiplying powers with the same base, add the exponents.
Thus, a³ × a⁵ = a⁸.
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The first part takes 2 hours and the second takes 1 hour.
The total travel time is 3 hours.
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When dividing powers with the same base, subtract the exponents.
Thus, x⁷ ÷ x³ = x⁴.
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The speed is 90 × 5/18 = 25 m/s, so total distance is 25 × 24 = 600 m.
Subtracting the train length gives a bridge length of 400 m.
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Square the coefficient and multiply the exponent by 2.
This gives 2²a⁶ = 4a⁶.
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Downwind speed is 300 km/h and upwind speed is 200 km/h.
Wind speed is half their difference: 50 km/h.
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To pass a pole, the train covers its own length.
Speed = 150 ÷ 10 = 15 m/s.
