Practice Pakistan questions with answers and explanations.
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The operations alternate between multiplying by 3 and dividing by 2.
After 18, multiply by 3 to get 54.
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Both letters in each pair advance by two positions.
After GJ comes IL.
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Every term is multiplied by 2.
Therefore, 56 × 2 = 112.
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Each term is the sum of the preceding two terms.
Thus, 5 + 8 = 13.
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The successive increases are 3, 4, 5, and 6.
The next increase is 7, so 28 + 7 = 35.
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The sequence skips one letter each time.
After G, the next alternate letter is I.
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The amounts subtracted are 9, 16, and 25, which are 3², 4², and 5².
Subtracting the next square, 6² = 36, gives 50 - 36 = 14.
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The sequence moves backward by two letters.
Two letters before T is R.
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The terms are factorials: 1!, 2!, 3!, and 4!.
The next term is 5! = 120.
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Each term advances by three alphabet positions.
K plus three letters gives N.
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Each term is obtained by doubling the previous term and adding 1.
Thus, 31 × 2 + 1 = 63.
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The letter positions are 1, 4, 9, and 16, which are perfect squares.
The next square is 25, corresponding to Y.
