What is the sum of the first 10 natural numbers?
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The sum of the first n natural numbers is n(n + 1)/2.
For n = 10, the sum is 10 × 11 ÷ 2 = 55.
Practice Pakistan questions with answers and explanations.
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The sum of the first n natural numbers is n(n + 1)/2.
For n = 10, the sum is 10 × 11 ÷ 2 = 55.
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The required percentage is 45/250 × 100.
This equals 18%.
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The sum of the first n odd numbers equals n².
For n = 8, the sum is 8² = 64.
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The score fraction is 42/50.
Multiplying by 100 gives 84%.
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The expression 2⁵ means multiplying five factors of 2.
Thus, 2 × 2 × 2 × 2 × 2 = 32.
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The square root is the number whose square equals 196.
Since 14 × 14 = 196, the answer is 14.
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The cube root is the number that gives 729 when cubed.
Since 9³ = 729, the answer is 9.
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The sequence increases by 3 each time.
Adding 3 to 11 gives 14.
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'Stationary' means not moving.
'Stationery' refers to writing materials.
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A number is divisible by 9 when the sum of its digits is divisible by 9.
For 5,832, the digit sum is 18.
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The possessive determiner 'Her' requires a noun in this position.
'Contribution' is the noun derived from 'contribute.'
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Since 12 × 13 = 156, subtracting gives 157 - 156 = 1.
Thus, the remainder is 1.