Pakistan MCQs

For a 1:1 salt, both ion concentrations equal the molar solubility s.
Therefore Ksp = s².

For a 1:1 salt, both ion concentrations equal the molar solubility s.
Therefore Ksp = s².

For a 1:1 salt, both ion concentrations equal the molar solubility s.
Therefore Ksp = s².

For a 1:1 salt, both ion concentrations equal the molar solubility s.
Therefore Ksp = s².

Average disappearance rate = decrease in concentration divided by time.
The positive magnitude is used for a reactant-disappearance rate.

Charles’s law gives V₁/T₁ = V₂/T₂.
V₂ = 2×500÷200 = 5 L.

Kc contains product concentrations over reactant concentrations.
Each concentration is raised to its stoichiometric coefficient.

Charles’s law gives V₁/T₁ = V₂/T₂.
V₂ = 4×400÷320 = 5 L.

Charles’s law gives V₁/T₁ = V₂/T₂.
V₂ = 6×300÷360 = 5 L.

PV = nRT, so P = nRT/V.
Substitution gives approximately 100 kPa.

PV = nRT, so P = nRT/V.
Substitution gives approximately 99.9 kPa.

PV = nRT, so P = nRT/V.
Substitution gives approximately 100 kPa.