Pakistan MCQs

Maximum height is H = u²sin²θ/(2g).
Substitution gives the stated value.

Range is R = u²sin2θ/g for equal launch and landing heights.
Substitution gives the stated value.

The sequence is 1600, 800, 400, 200.
That is three halvings, so three half-lives.

Use E=mc².
E=1×10^-6×(3×10^8)² = 9×10^10 J.

The x-component is A cos θ.
10 cos 0° = 10 N.

The x-component is A cos θ.
10 cos 60° = 5 N.

The x-component is A cos θ.
20 cos 30° = 17.32 N.

The x-component is A cos θ.
15 cos 90° = 0 N.

Fission can release neutrons that sustain a chain reaction.
It powers conventional nuclear reactors.

Percentage yield = actual yield ÷ theoretical yield × 100.
(45 ÷ 50) × 100 = 90%.

Fusion powers stars by converting a small amount of mass into energy.
It requires very high temperatures to overcome electric repulsion.

Boyle’s law gives P₁V₁ = P₂V₂.
P₂ = 100×4÷2 = 200 kPa.