A works three times as fast as B. Together they finish in 8 days. How long does A take alone?
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Let B's rate be 1 unit and A's 3 units, total 4 units.
A alone takes 8 × 4/3 = 32/3 days.
Practice Pakistan questions with answers and explanations.
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Let B's rate be 1 unit and A's 3 units, total 4 units.
A alone takes 8 × 4/3 = 32/3 days.
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The machine produces 60/5 = 12 units per hour.
In 8 hours it produces 12 × 8 = 96 units.
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If 40% takes 12 days, 10% takes 3 days.
The remaining 60% takes 18 days.
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The leak rate is 1/9 - 1/12 = 1/36 tank per hour.
Thus, the leak alone empties the tank in 36 hours.
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Speed equals distance divided by time.
Thus, 180 ÷ 3 = 60 km/h.
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Distance equals speed multiplied by time.
Thus, 72 × 2.5 = 180 km.
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To convert km/h to m/s, multiply by 5/18.
Thus, 54 × 5/18 = 15 m/s.
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To convert m/s to km/h, multiply by 18/5.
Thus, 20 × 18/5 = 72 km/h.
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Time equals distance divided by speed.
Thus, 12 ÷ 4 = 3 hours.
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Three taps together have three times the rate of one tap.
One tap therefore takes 3 × 6 = 18 hours.
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In 5 days, A completes 5/20 = 1/4 of the job.
Therefore, 3/4 remains.
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If half the work takes 6 days, the full work takes twice as long.
Thus, the total time is 12 days.