Mathematics reasoning: What is the sum of the first 10 natural numbers?
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The sum of the first n natural numbers is n(n + 1)/2.
For n = 10, the sum is 10 × 11 ÷ 2 = 55.
Practice AKU MBBS questions with answers and explanations.
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The sum of the first n natural numbers is n(n + 1)/2.
For n = 10, the sum is 10 × 11 ÷ 2 = 55.
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The sum of the first n odd numbers equals n².
For n = 8, the sum is 8² = 64.
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The least common multiple of 3 and 4 is 12.
A number divisible by both must therefore be divisible by 12.
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The units digits of powers of 7 cycle as 7, 9, 3, 1.
The fourth power therefore ends in 1.
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The greatest common divisor of 18 and 24 is 6.
Dividing both terms by 6 gives 3/4.
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Convert 2/3 to sixths: 2/3 = 4/6.
Then 4/6 + 1/6 = 5/6.
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The operation inside parentheses is completed first.
Then 12 ÷ 3 = 4.
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The multiplicative inverse of a nonzero fraction is its reciprocal.
Interchanging numerator and denominator gives 7/5.
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A composite number has more than two positive factors.
The number 4 has factors 1, 2, and 4.
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Precision describes repeatability.
Measurements can be precise without being accurate.
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The positive factors of 16 are 1, 2, 4, 8, and 16.
Therefore, it has 5 positive factors.
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Accuracy describes agreement with the true or accepted value.
Systematic error can reduce accuracy.