Senior-secondary mathematics task 120: In a sample of 30 items, 5 meet a condition. Enter the percentage, rounded to two decimals.
Percentage=(5/30)×100=16.67.
Practice china-gaokao-mathematics questions with answers and explanations.
Percentage=(5/30)×100=16.67.
Subtract 5 from both sides and divide by 6: x = (11-5)/6 = 1.
By Vieta’s formula, the sum of the roots equals the coefficient 12.
aₙ=a₁+(n−1)d=4+(16−1)×6=94.
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The sum is n(n+1)/2=36, so the mean is 36/8.
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The sum is n(n+1)/2=28, so the mean is 28/7.
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There are 2 favourable outcomes out of 9 equally likely outcomes, so P(red)=2/9.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=3x²+10x. Substituting x=3 gives 57.
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Use the circle-area formula A = πr². Substituting r = 3 gives A = π × 3² = 9π.
Percentage=(14/29)×100=48.28.
Subtract 4 from both sides and divide by 5: x = (59-4)/5 = 11.