Practice china-kaoyan-math-1 questions with answers and explanations.
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There are 3 favourable outcomes out of 8 equally likely outcomes, so P(red)=3/8.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
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The sum is n(n+1)/2=36, so the mean is 36/8.
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There are 2 favourable outcomes out of 6 equally likely outcomes, so P(red)=2/6.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=3x²+12x. Substituting x=2 gives 36.
An antiderivative is 2/2 x²+1x. At x=3, the value is 12.0.
The dot product is 2×3+2×2=10.
Rewrite the value using base 3: 27 = 3^3. Matching exponents gives x = 3.
aₙ=a₁+(n−1)d=9+(6−1)×2=19.
f′(x)=15x²+10x. Substituting x=1 gives 25.
An antiderivative is 1/2 x²+5x. At x=2, the value is 12.0.
