Practice china-kaoyan-math-1 questions with answers and explanations.
aₙ=a₁+(n−1)d=6+(15−1)×5=76.
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The sum is n(n+1)/2=15, so the mean is 15/5.
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There are 4 favourable outcomes out of 11 equally likely outcomes, so P(red)=4/11.
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The sum is n(n+1)/2=10, so the mean is 10/4.
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There are 3 favourable outcomes out of 9 equally likely outcomes, so P(red)=3/9.
The coordinate differences are 3 and 4, so the distance is √(3²+4²)=5.
f′(x)=6x²+4x. Substituting x=2 gives 32.
An antiderivative is 2/2 x²+2x. At x=3, the value is 15.0.
The dot product is 2×2+3×4=16.
Rewrite the value using base 2: 4 = 2^2. Matching exponents gives x = 2.
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Use the circle-area formula A = πr². Substituting r = 6 gives A = π × 6² = 36π.
Percentage=(5/40)×100=12.50.
