If 15 workers finish a job in 20 days, how many workers are needed to finish it in 12 days?
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Worker-days remain constant for the same job.
Thus, 15 × 20 ÷ 12 = 25 workers.
Practice ECAT questions with answers and explanations.
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Worker-days remain constant for the same job.
Thus, 15 × 20 ÷ 12 = 25 workers.
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Twenty-four workers complete 1/4 in 10 days, so the remaining 3/4 needs 30 equivalent days at the same workforce.
Only 20 days remain, requiring 36 workers, so 12 extra are needed.
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One-year compound amount is principal plus 12% interest.
Thus, 20,000 × 1.12 = Rs. 22,400.
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Twice the efficiency means twice the daily work rate.
Therefore, A takes half of 18 days, which is 9 days.
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Profit is shared in the ratio of investments, 3:5.
B receives 5/8 of Rs. 16,000 = Rs. 10,000.
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In 5 days, A completes 5/20 = 1/4 of the job.
Therefore, 3/4 remains.
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Capital-time products are 40,000 × 12 and 60,000 × 8.
Both equal 480,000, so the ratio is 1:1.
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If half the work takes 6 days, the full work takes twice as long.
Thus, the total time is 12 days.
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A's capital-time is 2 × 6 + 4 × 6 = 36 units.
B's is 3 × 12 = 36 units, so profits are equal.
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Their combined rate is 1/12 + 1/18 + 1/36 = 1/6.
Therefore, they finish in 6 days.
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A 20% profit gives a selling price of Rs. 960.
Since this is 80% of marked price, marked price = 960/0.8 = Rs. 1,200.
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Let B's rate be 2 units and A's rate be 3 units, total 5 units.
If 5 units finish in 6 days, B alone takes 6 × 5/2 = 15 days.