If 12 workers complete a task in 15 days, how many days will 20 workers take at the same rate?
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Workers and time are inversely proportional for fixed work.
Thus, 12 × 15 = 20 × days, giving 9 days.
Practice ECAT questions with answers and explanations.
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Workers and time are inversely proportional for fixed work.
Thus, 12 × 15 = 20 × days, giving 9 days.
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After a 20% increase, the quantity becomes 120% of the original.
The required reduction is 20/120 × 100 = 16⅔%.
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The sum is 12 + 18 + 20 + 30 = 80.
Dividing by 4 gives an average of 20.
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Convert each value to decimals: 5/8 = 0.625, 0.60 = 0.60, 59% = 0.59, and 3/5 = 0.60.
Therefore, 5/8 is the greatest.
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Total equals average multiplied by the number of values.
Thus, 24 × 5 = 120.
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Multiply 2 × 3 = 6 and count three decimal places in total.
The product is 0.006.
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The original total is 8 × 15 = 120.
After removing 22, the total is 98, and 98 ÷ 7 = 14.
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Multiply both numbers by 10 to remove decimals.
Then 48 ÷ 6 = 8.
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The original total age is 4 × 25 = 100 years.
The new total is 5 × 27 = 135, so the new age is 35.
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The third decimal digit is 6, so the second decimal digit is rounded up.
Thus, 18.746 becomes 18.75.
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The weighted sum is 70 × 2 + 90 × 3 = 410.
Dividing by the total weight 5 gives 82.
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The reciprocal of 0.25 is 1 ÷ 0.25.
Since 0.25 = 1/4, its reciprocal is 4.