Practice FAST-NU CS Engineering questions with answers and explanations.
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Speed equals distance divided by time.
Thus, 180 ÷ 3 = 60 km/h.
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In the same time, the faster runner covers 1,000 m while the slower covers 900 m.
Their speed ratio is therefore 1,000:900 = 10:9.
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Distance equals speed multiplied by time.
Thus, 72 × 2.5 = 180 km.
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Time is inversely proportional to speed.
The decrease is 1 - 50/60 = 1/6 = 16 2/3%.
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To convert km/h to m/s, multiply by 5/18.
Thus, 54 × 5/18 = 15 m/s.
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Let total distance be 3d; time is d/30 + 2d/60 = d/15.
Average speed is 3d ÷ (d/15) = 45 km/h.
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To convert m/s to km/h, multiply by 18/5.
Thus, 20 × 18/5 = 72 km/h.
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Travel time is 210 ÷ 70 = 3 hours.
Three hours after 8:00 a.m. is 11:00 a.m.
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Time equals distance divided by speed.
Thus, 12 ÷ 4 = 3 hours.
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Their closing speed is 20 + 25 = 45 km/h.
Time = 90 ÷ 45 = 2 hours.
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For equal distances, average speed is the harmonic mean 2ab/(a + b).
Thus, 2 × 40 × 60 ÷ 100 = 48 km/h.
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For equal time intervals, average speed is the arithmetic mean.
Thus, (40 + 60)/2 = 50 km/h.
