What is the sum of the first 10 natural numbers?
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The sum of the first n natural numbers is n(n + 1)/2.
For n = 10, the sum is 10 × 11 ÷ 2 = 55.
Practice GAT Subject Mathematics questions with answers and explanations.
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The sum of the first n natural numbers is n(n + 1)/2.
For n = 10, the sum is 10 × 11 ÷ 2 = 55.
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The required percentage is 45/250 × 100.
This equals 18%.
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Since 12 × 13 = 156, subtracting gives 157 - 156 = 1.
Thus, the remainder is 1.
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Division and multiplication have equal priority and are performed left to right.
So 48 ÷ 6 = 8, and 8 × 3 = 24.
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Multiplication is performed before addition.
Thus, 3 × 4 = 12 and 5 + 12 = 17.
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The operation inside parentheses is completed first.
Then 12 ÷ 3 = 4.
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The multiplicative inverse of a nonzero fraction is its reciprocal.
Interchanging numerator and denominator gives 7/5.
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A composite number has more than two positive factors.
The number 4 has factors 1, 2, and 4.
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The positive factors of 16 are 1, 2, 4, 8, and 16.
Therefore, it has 5 positive factors.
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Dividing 84 by primes gives 84 = 2 × 2 × 3 × 7.
This is 2² × 3 × 7.
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An irrational number cannot be expressed as a ratio of integers.
The number √2 has a nonterminating, nonrepeating decimal expansion.
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The expression 2⁵ means multiplying five factors of 2.
Thus, 2 × 2 × 2 × 2 × 2 = 32.