A 2 kg object accelerates from 3 m/s to 7 m/s. What is the change in kinetic energy?
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ΔK=½m(v²-u²).
With m=2, ΔK=49-9 = 40 J.
Practice GIKI Engineering Computing questions with answers and explanations.
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ΔK=½m(v²-u²).
With m=2, ΔK=49-9 = 40 J.
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Momentum is p=mv.
P=6×4 = 24 kg·m/s.
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Impulse equals change in momentum.
J=3(8-2)=18 N·s.
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Impulse is FΔt for constant force.
50×0.2 = 10 N·s.
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Conserve momentum: 2×6 = (2+4)v.
V=12/6 = 2 m/s.
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Total momentum is 3×4+1×2=14 kg·m/s.
Total mass is 4 kg, so v=3.5 m/s.
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Take initial velocity as +5 and final as -3.
|Δp|=|2(-3-5)|=16 kg·m/s.
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Torque is force times perpendicular distance.
τ=10×0.5 = 5 N·m.
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Torque is rF sinθ.
τ=2×20×sin30° = 20 N·m.
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Angular velocity is angular displacement divided by time.
ω=10/2 = 5 rad/s.
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Angular acceleration is change in angular velocity over time.
α=(16-4)/3 = 4 rad/s².
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Linear speed is v=rω.
V=0.5×8 = 4 m/s.