Practice GIKI Engineering Computing questions with answers and explanations.
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Thirty percent of 20 liters is 0.30 × 20.
This equals 6 liters.
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The solution contains 4 liters of salt, which remains unchanged.
For salt to be 25%, total volume must be 16 liters, so 6 liters are added.
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For direct variation, x/y is constant.
The constant is 18/6 = 3, so x = 3 × 10 = 30.
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Let the number be x, so 0.40x = 72.
Dividing by 0.40 gives x = 180.
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Percent means per hundred.
Thus, 3.5% = 3.5 ÷ 100 = 0.035.
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The required percentage is 45/250 × 100.
This equals 18%.
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The score fraction is 42/50.
Multiplying by 100 gives 84%.
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Starting from 100, a 10% increase gives 110.
A 10% decrease from 110 gives 99, which is 1% lower.
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After a 20% increase, the quantity becomes 120% of the original.
The required reduction is 20/120 × 100 = 16⅔%.
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Convert each value to decimals: 5/8 = 0.625, 0.60 = 0.60, 59% = 0.59, and 3/5 = 0.60.
Therefore, 5/8 is the greatest.
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Multiply 2 × 3 = 6 and count three decimal places in total.
The product is 0.006.
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Multiply both numbers by 10 to remove decimals.
Then 48 ÷ 6 = 8.
