Practice GIKI Management Sciences questions with answers and explanations.
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Worker-days remain constant for the same job.
Thus, 15 × 20 ÷ 12 = 25 workers.
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Twice the efficiency means twice the daily work rate.
Therefore, A takes half of 18 days, which is 9 days.
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In 5 days, A completes 5/20 = 1/4 of the job.
Therefore, 3/4 remains.
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If half the work takes 6 days, the full work takes twice as long.
Thus, the total time is 12 days.
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Their combined rate is 1/12 + 1/18 + 1/36 = 1/6.
Therefore, they finish in 6 days.
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Let B's rate be 2 units and A's rate be 3 units, total 5 units.
If 5 units finish in 6 days, B alone takes 6 × 5/2 = 15 days.
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Their daily rate is 1/16 + 1/24 = 5/48.
In 4 days they do 5/12, so 7/12 remains.
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Using SI = PRT/100, 900 = P × 6 × 3/100.
Solving gives P = Rs. 5,000.
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Each year, 90% of the previous value remains.
Thus, 50,000 × 0.9² = Rs. 40,500.
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Rate = SI × 100 ÷ (P × T).
Thus, 800 × 100 ÷ (4,000 × 5) = 4%.
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Compound growth gives 20,000 × 1.05².
The result is 22,050.
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Compound amount is P(1 + r)².
Thus, 10,000 × 1.1² = Rs. 12,100.
