A can complete a task in 10 days and B in 15 days. How long will they take together?
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Their combined daily rate is 1/10 + 1/15 = 1/6.
Therefore, they complete the job in 6 days.
Practice HAT questions with answers and explanations.
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Their combined daily rate is 1/10 + 1/15 = 1/6.
Therefore, they complete the job in 6 days.
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For two years, the difference is P(r/100)².
So 10,000 × 0.1² = Rs. 100.
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B's rate is 1/8 - 1/12 = 1/24.
Therefore, B alone needs 24 days.
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Doubling means interest equal to the principal is earned in 8 years.
Tripling requires interest equal to twice the principal, so it takes 16 years.
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Worker-days remain constant for the same job.
Thus, 15 × 20 ÷ 12 = 25 workers.
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One-year compound amount is principal plus 12% interest.
Thus, 20,000 × 1.12 = Rs. 22,400.
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Twice the efficiency means twice the daily work rate.
Therefore, A takes half of 18 days, which is 9 days.
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Profit is shared in the ratio of investments, 3:5.
B receives 5/8 of Rs. 16,000 = Rs. 10,000.
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In 5 days, A completes 5/20 = 1/4 of the job.
Therefore, 3/4 remains.
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Capital-time products are 40,000 × 12 and 60,000 × 8.
Both equal 480,000, so the ratio is 1:1.
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If half the work takes 6 days, the full work takes twice as long.
Thus, the total time is 12 days.
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A's capital-time is 2 × 6 + 4 × 6 = 36 units.
B's is 3 × 12 = 36 units, so profits are equal.