What is the area of a triangle with base 10 cm and height 6 cm?
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Triangle area is one-half × base × height.
Thus, 1/2 × 10 × 6 = 30 cm².
Practice HAT questions with answers and explanations.
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Triangle area is one-half × base × height.
Thus, 1/2 × 10 × 6 = 30 cm².
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Parallelogram area is base times perpendicular height.
Thus, 15 × 8 = 120 cm².
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Area is one-half × sum of parallel sides × height.
Thus, 1/2 × 22 × 5 = 55 cm².
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Circumference is 2πr.
Thus, 2 × 22/7 × 7 = 44 cm.
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Triangle angles sum to 180°.
The third angle is 180° - 45° - 65° = 70°.
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One complete revolution corresponds to 360 degrees.
Therefore, the central angle of a full circle is 360°.
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All three angles are equal and their sum is 180°.
Therefore, each angle is 180° ÷ 3 = 60°.
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A tangent to a circle is perpendicular to the radius drawn to the contact point.
The angle between them is 90°.
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Equal sides in an isosceles triangle face equal angles.
This is the base-angle theorem.
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Corresponding angles between parallel lines are equal.
Therefore, the other angle is also 110°.
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By Pythagoras, c² = 6² + 8² = 100.
Thus, c = 10 cm.
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Alternate interior angles formed by parallel lines are equal.
Thus, the matching angle is 65°.