Practice india-cet-ap-eapcet questions with answers and explanations.
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s=vt=48 m.
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KE=½mv²=364.5 J.
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V=IR=10 V.
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R=11 Ω.
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mgh=40 J.
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By Vieta, α+β=16.
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Determinant=9×10=90.
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|v|²=10²+4²=116.
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f′(x)=2x, so f′(2)=4.
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(3+8)/2=5.5.
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s=vt=27 m.
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KE=½mv²=36.0 J.
