Practice india-cet-gujcet questions with answers and explanations.
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KE=½mv²=171.5 J.
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V=IR=24 V.
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R=15 Ω.
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mgh=20 J.
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s=vt=15 m.
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By Vieta, α+β=12.
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Determinant=7×8=56.
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|v|²=8²+10²=164.
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f′(x)=2x, so f′(9)=18.
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(10+6)/2=8.0.
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s=vt=56 m.
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KE=½mv²=64.0 J.
