Practice india-cet-keam questions with answers and explanations.
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s=vt=15 m.
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KE=½mv²=108.0 J.
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V=IR=63 V.
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R=13 Ω.
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mgh=90 J.
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KE=½mv²=32.0 J.
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By Vieta, α+β=10.
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Determinant=6×7=42.
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|v|²=7²+9²=130.
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f′(x)=2x, so f′(8)=16.
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(9+5)/2=7.0.
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s=vt=42 m.
