Practice india-cet-mht-cet questions with answers and explanations.
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KE=½mv²=243.0 J.
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V=IR=35 V.
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R=16 Ω.
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mgh=90 J.
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R=12 Ω.
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mgh=70 J.
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s=vt=40 m.
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KE=½mv²=288.0 J.
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V=IR=8 V.
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By Vieta, α+β=12.
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Determinant=3×4=12.
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|v|²=4²+6²=52.
