Common Test Mathematics I/A practice 19: How many ways can 3 students be selected from 11 students?
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Use combinations: C(11,3) = 165.
Practice japan-common-test-math-ia questions with answers and explanations.
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Use combinations: C(11,3) = 165.
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Probability = favourable outcomes ÷ total outcomes.
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Mean = (14 + 13 + 5 + 27)/4 = 14.75.
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Probability = favourable outcomes ÷ total outcomes.
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Mean = (7 + 11 + 4 + 18)/4 = 10.
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f(7)=4×7+8=36.
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10% of 46 = 4.6.
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Area = 2 × 12 = 24 cm².
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By Vieta’s formula, the sum of the roots is the coefficient of x with sign changed.
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By Vieta’s formula, the sum of the roots is the coefficient of x with sign changed.
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Use combinations: C(9,2) = 36.
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Probability = favourable outcomes ÷ total outcomes.