Common Test Mathematics II/B/C practice 27: For f(x)=5x²+5x, find f′(7).
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f′(x)=10x+5; substitute x=7.
Practice japan-common-test-math-iibc questions with answers and explanations.
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f′(x)=10x+5; substitute x=7.
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An antiderivative is 6x²+1x, giving 392.
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log x + log y = log(xy).
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The sum is 3(1+…+5)=3×15=45.
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Scalar multiplication multiplies every component.
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Scalar multiplication multiplies every component.
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f′(x)=10x+6; substitute x=7.
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An antiderivative is 6x²+2x, giving 400.
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The conjugate changes the sign of the imaginary part.
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z=(x−mean)/sd=2.
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Repeated multiplication gives 31381059609.
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The sum is 3(1+…+5)=3×15=45.