JEE Advanced Mathematics NAT numerical 3067: Enter the positive value of |10²−4|.
Correct Answer: 96
Explanation:
96
MCQ Collection
jee-advanced-numerical MCQs
Practice jee-advanced-numerical questions with answers and explanations.
JEE Advanced Mathematics NAT numerical 3068: Enter the area of a triangle with base 11 and height 9.
Correct Answer: 49.5
Explanation:
Area=½×11×9=49.5.
JEE Advanced Mathematics NAT numerical 3069: A sequence starts at 26 and each term is three times the preceding term. Enter the second term.
Correct Answer: 78
Explanation:
78
JEE Advanced Chemistry NAT numerical 3058: Enter the area of a triangle with base 24 and height 10.
Correct Answer: 120
Explanation:
Area=½×24×10=120.0.
JEE Advanced Chemistry NAT numerical 3059: A sequence starts at 17 and each term is three times the preceding term. Enter the second term.
Correct Answer: 51
Explanation:
51
JEE Advanced Mathematics NAT numerical 3060: Evaluate 3(3+1).
Correct Answer: 12
Explanation:
3×4=12.
JEE Advanced Mathematics NAT numerical 3061: If the roots of z²−12z+32=0 are r and s, enter r+s.
Correct Answer: 12
Explanation:
Vieta gives r+s=12.
JEE Advanced Mathematics NAT numerical 3062: Enter the positive value of |5²−13|.
Correct Answer: 12
Explanation:
12
JEE Advanced Chemistry NAT numerical 3047: Enter the positive value of |13²−6|.
Correct Answer: 163
Explanation:
163
JEE Advanced Chemistry NAT numerical 3048: Enter the area of a triangle with base 14 and height 11.
Correct Answer: 77
Explanation:
Area=½×14×11=77.0.
JEE Advanced Chemistry NAT numerical 3049: A sequence starts at 31 and each term is three times the preceding term. Enter the second term.
Correct Answer: 93
Explanation:
93
JEE Advanced Chemistry NAT numerical 3050: Evaluate 16(4+1).
Correct Answer: 80
Explanation:
16×5=80.