JEE Main Chemistry numerical 251: If the roots of z²−40z+391=0 are r and s, enter r+s.
Correct Answer: 40
Explanation:
Vieta gives r+s=40.
Practice jee-main-paper-1 questions with answers and explanations.
Vieta gives r+s=40.
96
17×5=85.
190
Area=½×15×11=82.5.
99
2×15=30.
Vieta gives r+s=22.
9
Area=½×5×12=30.0.
69
7×6=42.