JEE Main Mathematics numerical 190: Evaluate 8(18+1).
Correct Answer: 152
Explanation:
8×19=152.
MCQ Collection
jee-main-paper-1 MCQs
Practice jee-main-paper-1 questions with answers and explanations.
JEE Main Mathematics numerical 191: If the roots of z²−15z+54=0 are r and s, enter r+s.
Correct Answer: 15
Explanation:
Vieta gives r+s=15.
JEE Main Mathematics numerical 192: Enter the positive value of |10²−11|.
Correct Answer: 89
Explanation:
89
JEE Main Mathematics numerical 193: Enter the area of a triangle with base 11 and height 16.
Correct Answer: 88
Explanation:
Area=½×11×16=88.0.
JEE Main Mathematics numerical 194: A sequence starts at 16 and each term is three times the preceding term. Enter the second term.
Correct Answer: 48
Explanation:
48
JEE Main Chemistry item 180: Which species donates an electron pair according to Lewis theory?
Choose an option to check your answer.
Correct Answer: A. Lewis base
Explanation:
A Lewis base donates an electron pair.
JEE Main Mathematics numerical 181: If the roots of z²−29z+154=0 are r and s, enter r+s.
Correct Answer: 29
Explanation:
Vieta gives r+s=29.
JEE Main Chemistry item 176: What is the hybridisation of carbon in methane?
Choose an option to check your answer.
Correct Answer: B. sp3
Explanation:
Four sigma bonds require tetrahedral sp3 hybridisation.
JEE Main Chemistry item 177: Which law relates gas volume and absolute temperature at constant pressure?
Choose an option to check your answer.
Correct Answer: B. Charles law
Explanation:
Charles law states V∝T at constant pressure.
JEE Main Chemistry item 178: Which orbital fills after 3p in the ground-state Aufbau sequence?
Choose an option to check your answer.
Correct Answer: A. 4s
Explanation:
The common Aufbau order places 4s before 3d.
JEE Main Chemistry item 179: Oxidation is best described as what?
Choose an option to check your answer.
Correct Answer: B. Loss of electrons
Explanation:
Oxidation is electron loss.
JEE Main Chemistry item 171: What is the hybridisation of carbon in methane?
Choose an option to check your answer.
Correct Answer: C. sp3
Explanation:
Four sigma bonds require tetrahedral sp3 hybridisation.