What is the magnitude of a vector with components 3 and 4?
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Use the Pythagorean theorem for perpendicular components.
Magnitude = √(3²+4²)=5.
Practice MDCAT 2026 questions with answers and explanations.
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Use the Pythagorean theorem for perpendicular components.
Magnitude = √(3²+4²)=5.
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The x-component is A cosθ.
10 cos60° = 10×0.5 = 5.
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The y-component is A sinθ.
10 sin30° = 10×0.5 = 5.
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Molarity equals moles divided by liters of solution.
0.50/2.0 = 0.25 M.
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Vectors in the same direction add directly.
The resultant is 12+7 = 19 N.
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Atomic number identifies the element.
In a neutral atom it also equals the number of electrons.
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Opposite collinear vectors subtract in magnitude.
The resultant magnitude is |12-7| = 5 N.
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Mass number applies to a specific isotope.
It is always a whole number.
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Displacement is a vector from initial to final position.
It can be zero even when distance traveled is not zero.
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Isotopes have the same atomic number but different mass numbers.
Their chemical behavior is usually similar.
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Distance is a scalar and depends on the actual path.
It is always nonnegative.
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Ions form by gaining or losing electrons.
Cations are positive and anions are negative.