MCQ Collection
MDCAT 2026 MCQs
Practice MDCAT 2026 questions with answers and explanations.
Choose an option to check your answer.
Correct Answer: C. HF
Explanation:
Atomic orbitals and electron-pair repulsions determine bonding and molecular shape.
The stated option follows the relevant electronic or VSEPR rule.
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Correct Answer: D. Head-on orbital overlap
Explanation:
Atomic orbitals and electron-pair repulsions determine bonding and molecular shape.
The stated option follows the relevant electronic or VSEPR rule.
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Correct Answer: A. Sideways overlap of parallel p orbitals
Explanation:
Atomic orbitals and electron-pair repulsions determine bonding and molecular shape.
The stated option follows the relevant electronic or VSEPR rule.
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Correct Answer: B. CH₄
Explanation:
Atomic orbitals and electron-pair repulsions determine bonding and molecular shape.
The stated option follows the relevant electronic or VSEPR rule.
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Correct Answer: C. 12 m/s
Explanation:
Conservation of mass for steady incompressible flow gives A₁v₁=A₂v₂.
Solving gives the stated speed.
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Correct Answer: D. 2 m/s
Explanation:
Conservation of mass for steady incompressible flow gives A₁v₁=A₂v₂.
Solving gives the stated speed.
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Correct Answer: A. 2.5 m/s
Explanation:
Conservation of mass for steady incompressible flow gives A₁v₁=A₂v₂.
Solving gives the stated speed.
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Correct Answer: B. 4 m/s
Explanation:
Conservation of mass for steady incompressible flow gives A₁v₁=A₂v₂.
Solving gives the stated speed.
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Correct Answer: C. 6000 Pa
Explanation:
For horizontal flow, P + ½ρv² is constant.
The pressure drop is ½ρ(v₂²−v₁²).
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Correct Answer: D. 8000 Pa
Explanation:
For horizontal flow, P + ½ρv² is constant.
The pressure drop is ½ρ(v₂²−v₁²).
Choose an option to check your answer.
Correct Answer: A. 6000 Pa
Explanation:
For horizontal flow, P + ½ρv² is constant.
The pressure drop is ½ρ(v₂²−v₁²).
Choose an option to check your answer.
Correct Answer: B. 3000 Pa
Explanation:
For horizontal flow, P + ½ρv² is constant.
The pressure drop is ½ρ(v₂²−v₁²).