A projectile is launched from level ground at 30 m/s and 45°. Using g = 10 m/s², what is its time of flight?
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Time of flight is T = 2u sinθ/g.
Substitution gives the stated value.
Practice MDCAT 2026 questions with answers and explanations.
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Time of flight is T = 2u sinθ/g.
Substitution gives the stated value.
Choose an option to check your answer.
For rate ∝ [A]ⁿ, the rate factor equals the concentration factor raised to n.
The observed change gives the stated order.
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Maximum height is H = u²sin²θ/(2g).
Substitution gives the stated value.
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For rate ∝ [A]ⁿ, the rate factor equals the concentration factor raised to n.
The observed change gives the stated order.
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Range is R = u²sin2θ/g for equal launch and landing heights.
Substitution gives the stated value.
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For rate ∝ [A]ⁿ, the rate factor equals the concentration factor raised to n.
The observed change gives the stated order.
Choose an option to check your answer.
Time of flight is T = 2u sinθ/g.
Substitution gives the stated value.
Choose an option to check your answer.
An equilibrium shifts in the direction that opposes the imposed change.
Applying this rule gives the stated direction.
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For a 1:1 salt, both ion concentrations equal the molar solubility s.
Therefore Ksp = s².
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For a 1:1 salt, both ion concentrations equal the molar solubility s.
Therefore Ksp = s².
Choose an option to check your answer.
For a 1:1 salt, both ion concentrations equal the molar solubility s.
Therefore Ksp = s².
Choose an option to check your answer.
For a 1:1 salt, both ion concentrations equal the molar solubility s.
Therefore Ksp = s².