MDCAT 2026 MCQs

Moles = mass ÷ molar mass = 117 ÷ 58.5.
The sample therefore contains 2 mol.

Elimination often removes H and another group from adjacent atoms.
It commonly forms an alkene.

Moles = mass ÷ molar mass = 16 ÷ 32.
The sample therefore contains 0.5 mol.

Complete combustion gives carbon dioxide and water.
Limited oxygen may produce carbon monoxide or soot.

Moles = mass ÷ molar mass = 64 ÷ 32.
The sample therefore contains 2 mol.

Hydrogenation converts an unsaturated bond toward saturation.
A metal catalyst is commonly used.

Moles = mass ÷ molar mass = 50 ÷ 100.
The sample therefore contains 0.5 mol.

Esterification is a condensation reaction.
An acid catalyst is often used.

Moles = mass ÷ molar mass = 200 ÷ 100.
The sample therefore contains 2 mol.

Hydrolysis breaks susceptible bonds using water components.
Esters, amides, and biological polymers can undergo hydrolysis.

Number of particles = moles × Avogadro constant.
0.25 × 6.02×10²³ = 1.5e+23.

Polymers contain repeated structural units.
They may form by addition or condensation processes.