Two coherent waves arrive 180° out of phase with amplitudes 5 cm and 3 cm. What is the resultant amplitude?
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Opposite-phase amplitudes subtract.
The resultant amplitude is |5-3| = 2 cm.
Practice MDCAT 2026 questions with answers and explanations.
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Opposite-phase amplitudes subtract.
The resultant amplitude is |5-3| = 2 cm.
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Greater wave amplitude generally means greater intensity.
Perceived loudness is also frequency-dependent.
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For the fundamental, the string length is half a wavelength.
λ=2L=2.4 m.
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Approach raises observed frequency, while separation lowers it.
The effect occurs for sound and electromagnetic waves.
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The fundamental wavelength is 2L=1.5 m.
F=v/λ=300/1.5 = 200 Hz.
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Frequency is cycles divided by time.
20/5 = 4 Hz.
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For an open pipe, fundamental wavelength is 2L=1.7 m.
F=340/1.7 = 200 Hz.
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Period is the reciprocal of frequency.
T=1/5 = 0.2 s.
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For a closed pipe, fundamental wavelength is 4L=3.4 m.
F=340/3.4 = 100 Hz.
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Use v=fλ.
λ=12/3 = 4 m.
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Electric charge occurs in positive and negative forms.
Like charges repel and unlike charges attract.
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Wave speed is v=fλ.
V=8×2.5 = 20 m/s.