Practice NAT questions with answers and explanations.
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An event and its complement have total probability 1.
Thus, P(not A) = 1 - 0.35 = 0.65.
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A horizontal line has a constant y-coordinate.
Therefore, an equation of the form y = constant is horizontal.
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For independent events, multiply their probabilities.
Thus, 1/2 × 1/3 = 1/6.
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A vertical line has a constant x-coordinate.
Therefore, x = -3 represents a vertical line.
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There are 2 favorable blue balls out of 5 total balls.
The probability is therefore 2/5.
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The inner rectangle measures 46 m by 26 m, with area 1,196 m².
The full area is 1,500 m², so the path area is 304 m².
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The probability is 4/10 × 3/9.
This simplifies to 12/90 = 2/15.
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The intersection contains elements common to both sets.
Only 3 appears in both A and B.
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Three distinct objects can be arranged in 3! ways.
Thus, 3! = 3 × 2 × 1 = 6.
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The union contains every distinct element from either set.
Thus, A ∪ B = {1, 2, 3}.
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The number of arrangements of 5 distinct objects is 5!.
Thus, 5! = 120.
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The complement contains universal-set elements not in A.
Removing 2 and 4 leaves 1, 3, and 5.
