What is the magnitude of a vector with components 3 and 4?
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Use the Pythagorean theorem for perpendicular components.
Magnitude = √(3²+4²)=5.
Practice PIEAS ICS questions with answers and explanations.
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Use the Pythagorean theorem for perpendicular components.
Magnitude = √(3²+4²)=5.
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The x-component is A cosθ.
10 cos60° = 10×0.5 = 5.
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The y-component is A sinθ.
10 sin30° = 10×0.5 = 5.
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Vectors in the same direction add directly.
The resultant is 12+7 = 19 N.
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Opposite collinear vectors subtract in magnitude.
The resultant magnitude is |12-7| = 5 N.
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Displacement is a vector from initial to final position.
It can be zero even when distance traveled is not zero.
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Distance is a scalar and depends on the actual path.
It is always nonnegative.
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Random errors cause scatter around a central value.
Repeated measurements and averaging can reduce their effect.
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Leading zeros are not significant, but trailing zeros after a decimal are.
Thus 4, 5, and the final zero are significant.
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Vector addition replaces multiple vectors with an equivalent single vector.
Its direction and magnitude depend on the original vectors.
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Convert 1/4 to 2/8.
Then 7/8 - 2/8 = 5/8.
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Perpendicular vector components form a right triangle.
The resultant magnitude is found from the sum of squared components.